In this question, we made a license that does not allow repeated digit and letter. That means the probability count of letter and digit will be decreased by 1 for every roll.
There is 10 kinds of digits (0-9) and 26 kinds of letters (a to z). So, 2 digits and 5 letter would be:
(10 * 9) * (26 * 25 * 24 * 23 * 22)= 710424000 kinds of license plates
P(5 on one throw) = 1/8
expected number of 5's in 400 throws = 1/8 * 400 = 50
Answer:
(a) 2ab - a/b
(b) c² + d + 2cd
(c) c + c²
(d) Let x be the number that is 1 greater than b, then x = b + 1
Let y be the number twice as large as b, then y = 2b
Then the quotient of x and y is what we want. This is (b + 1)/2b
(e) pq - 3(p + q)
(f) The quotient of n² and n³ + 5, this is
n²/(n³ + 5)
Answer:
12 years
Step-by-step explanation:
1 inch = two years
6x2=12
Answer:
Step-by-step explanation:
3x^2+3x-6
