Answer:
Step-by-step explanation:
Question says that it uses 120 feet of fencing material to enclose three sides of the play area. This means there are 3 sides. Putting this into equation, we have something like this.
120 = L + 2W
Where
LW = area.
Again, in order to maximize the area with the given fencing, from the equation written above, then Width, w must be = 30 feet and length, l must be = 60
On substituting, we have
A = LW = (120 - 2W) W
From the first equation, making L the subject of the formula, we have this
L = 120 - 2W, which then we substituted above.
On simplification, we have
L = 120W -2W²
Differentiating, we have
A' = 120 - 4W = 0
Remember that W = 30
So therefore, L = 120 - 2(30) = 60 feet
Answer:
The answer is definitely Option A
2L + 2W = 48
L= 15 feet
substitute the given value to the formula provided.
2(15) + 2W = 48
multiply 2 by 15
30 + 2W = 48
use the subtraction property of equality to cancel the value 30 on the left side.
30 - 30 + 2W = 48 - 30
cancel 30 on the left side leaving 2W while subtract 30 from 48.
2W = 18
divide both sides to get the value of the width.
2W/2 = 18/2
W = 9ft this is the final answer.
