Answer:
i think it's c
Step-by-step explanation:
a. <u>2</u><u>/</u><u>1</u><u>00</u><u> </u><u>×</u><u> </u><u>1</u><u>5</u><u>0</u><u>=</u><u> </u><u>3</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>b</u><u>. </u><u> </u><u>100×</u><u>4</u><u>0</u><u>0</u><u>=</u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u>c</u><u>. </u><u> </u><u> </u><u>6</u><u>/</u><u>100 </u><u>×</u><u>6</u><u>0</u><u>=</u><u> </u><u>1</u><u>.</u><u>2</u><u> </u><u>×</u><u>3</u><u>=</u><u>3</u><u>.</u><u>6</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>d</u><u>. </u><u>6</u><u>9</u><u>×</u><u>5</u><u>0</u><u>=</u><u>3</u><u>4</u><u>0</u><u>0</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>so </u><u>answer</u><u> </u><u>c</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u> </u>
Check the picture below
surely you know how much that is.
Answer:
Yes
Step-by-step explanation:
Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.
When both machines work for 20 minutes
Machine A would produce = widget and
Machine B would produce = widgets
So we can say that Machine A would produce more widgets than Machine N at that time.
Answer is Yes
Answer:
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Step-by-step explfdsanation:
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