the probability that if you pick only one, it's defective, is 250/6700
Therefore, the probability that one is not defective is 6450/6700
a. You want all 4 to not be defective: (6450/6700)^4
b. all 100 have to be not defective: (6450/6700)^100
If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.
Answer:
c) 1
Step-by-step explanation:
=> ax+y = 5
<u><em>Putting x =2, y =3</em></u>
=> a(2)+3 = 5
=> 2a = 5-3
=> 2a = 2
<em>Dividing both sides by 2</em>
=> a = 1