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Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
Step-by-step explanation:
if the two integers are x and y
xy=-10
x+y=-9
x+(-10/x)=-9
x2+9x-10=0
(x-1)(x+10)=0
x=1 or x=-10
if x=1, y=-10
if x=-10, y=1
so the two integers are 1 and -10
Answer:
Because (-x²+2x+3)+(-x²-2x-1) = -x²+2x+3-x²-2x-1 = -2x²+2
Step-by-step explanation:
Hope It Helps!
