What is 5/10 - 3/20 equal Too?

marissa [1.9K]

Answer: Divide 6/42 by 6/6 to get 1/7

Step-by-step explanation: To find the numerator when dividing by 6/6, divide 6/6 to get 1. To find the denominator, divide 42/6 to get 7.

6 0

2 years ago

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Question 2 of 10

kobusy [5.1K]

Answer:

B

Step-by-step explanation:

4 0

2 years ago

Given f(x) and g(x) = f(x + k), use the graph to determine the value of k.

salantis [7]

Answer:

$g(x)=f(x+6)$

$k=6$

Step-by-step explanation:

Given:

$g(x)=f(x+k)$

Function transformation rule used:

$g(x)=f(x+k)$

If value of $k>1$ then the graph shifts $k$ units to the left.

If value of $k$ then the graph shifts $k$ units to the right.

From the graph, it is clear that the function $g(x)$ has moved 6 units(-4 to-10) to the left of $f(x)$ . This shows that the value of $k>1$ and it is $=6\ units$

Thus the transformation rule can be given as:

$g(x)=f(x+6)$

∴ $k=6$

6 0

2 years ago

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The fragment of a function given by the formula y = ax ^ 2 passes through the points of the coordinate plane (-3; 18) and (1; c)

devlian [24]

Answer:

Step-by-step explanation:

When you measure cones, in which directions you should click on the dots

representing cones.

5 0

1 year ago

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Solve the system of equations.

emmainna [20.7K]

$x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }$

<h2>Explanation:</h2>

We have the following system of three linear equations:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}$

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by $-5/2$ and add the result to the second equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}$

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}$

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

$\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}$

Step 4: solve for z.

$\begin{aligned} \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\ z & = \frac{ 21 }{ 113 } \end{aligned}$

Step 5: solve for y.

$\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}$

Step 6: solve for x by substituting $y=-\frac{208}{113}$ and $z = \frac{21}{113}$ into the first equation:

$2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}$

Finally:

$x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }$

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0

3 years ago