Explain the increase in pressure of a gas when its volume is decreased at constant temperature.
1 answer:
Answer:
For a gas held at constant temperature, we can apply Boyle's law, which states that the product between the gas pressure and its volume is constant:
where
P is the pressure
V is the volume
As we see from the equation, P and V are inversely proportional to each other: this means that when the volume is decreased, the pressure increases, and vice-versa. The reason for that is that when the volume is decreased, the gas is compressed, so the molecules of the gas come closer to each other, so they collide more frequently with the wall of the container, exerting therefore a greater pressure.
You might be interested in
Answer:
Explanation:
It is given that,
Diameter of cylinder, d = 6.6 cm
Radius of cylinder, r = 3.3 cm = 0.033 m
Acceleration of the string,
Displacement, d = 1.3 m
The angular acceleration is given by :
The angular displacement is given by :
Using the third equation of rotational kinematics as :
Here,
Since, 1 rad/s = 9.54 rpm
So,
So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.