The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
D
Step-by-step explanation:
Answer: yes it is
Step-by-step explanation:
Answer:
6^-1
Step-by-step explanation:
6^-6 - (-5) = 6^(-6 + 5) = 6^(-1)
A lot of things are going on in this question. Notice how the 5 is handled. It starts off in the denominator as - 5 and when brought to the numerator it becomes -(-5) which makes it + 5.
The answer is then easy. It is 6^(-6 + 5) = 6^-1
You could give the answer as 1/6 but that is not what the question says.
Answer:
15
<em>Hope that helps! :)</em>
<em></em>
<em>-Aphrodite</em>
Step-by-step explanation:
