The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²
If you already have an equation, all you have to do is locate the slope and look after it. But if it's in a graph, it's where the line is crossing the y-axis.
An example of the equation would be
y=2x+3
y=mx+b
2 would be m which is slope
and 3 would be b which is the y-intercept
Answer:
Assuming that the scale is 1, x int: (-4,0), y int: (0,-3)
Step-by-step explanation:
Hope this helps :)
What is the interquartile range for the data set 4,7,7,3,5,2,6,7,9 the answers are 3.5, 5.6, 7,9
polet [3.4K]
5.6 is the answer for your question