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2 years ago

fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula

1 answer:

7 0

Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

$A_{4} =6+ \dfrac{1}{(4+1)^2} =6+ \dfrac{1}{25}= \dfrac{151}{25} \\

 A_{6} =6+ \dfrac{1}{(6+1)^2} =6+ \dfrac{1}{49}= \dfrac{295}{49} \\

 A_{13} =6+ \dfrac{1}{(13+1)^2} =6+ \dfrac{1}{196}= \dfrac{1177}{196} \\
$

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