The sum of all angles of a triangle is equal to 180°
On a isosceles triangle, the base angles are the same.
We add them together 56° + 56° = 112°
To know X, we subtract 112° from the total
180° - 112° = 68°
X = 68°
OR as an equation
56 + 56 + x = 180
112 + x = 180
x = 180 - 112
x = 68
Answer:
6. E
7. D
8. 5,-8,34
Step-by-step explanation:
A. Parallel to the y-axis and passes through the point (3,5)
For it to be parallel to the y-axis, what this means is that it has an x-intercept and no y intercept.
So what this means is that x = 3 is our line so E is correct
B. Perpendicular to the y-axis means it is parallel to the x-axis
It means is has no x intercept and thus its x value at any point in time is zero
So the equation is y = -5
or simply y + 5 = 0 which means D is correct
C. It is parallel to the line 5x -8y + 12 = 0
Thus: 8y = 5x + 12
dividing both sides by 8
y = 5x/8 + 12/8
y = 5x/8 + 3/2
y = 5x/8 + 1.5
Comparing this with the general equation of a straight line ;
y = mx + c
where m is that slope, this means that 5/8 is the slope of the line
Mathematically if two lines are parallel, they have equal slopes.
So we can say the slope of the other line too is 5/8
Now to find the equation of the other line, we can use the point-slope method
y-y1 = m(x-x1)
where (x1,y1) in this case is (-2,3)
So we have;
y-3 = m(x-(-2))
y-3 = 5/8 (x + 2)
8(y-3) = 5(x + 2)
8y -24 = 5x + 10
5x + 10 + 24 -8y = 0
5x -8y + 34 = 0
So A, B, C = 5, -8, 34
8/7-1/3
Make both fractions have the same common denominator
24/21 - 7/21
Subtract the numerators while keeping the denominator the same
Final Answer: C. 17/21
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Answer:
μ = 1 The firm expects that one oil exploration will be successful.
v(x)= 0.9
Step-by-step explanation:
The first step is to define the random variable x as:
x: number of oil explorations being succesful
Then x can be take this values:
x = 0 , x =1 ... x =10
x is a binomially distributed random variable with parameters.
p = 0.1 and n=10
And the mean or the expected value of x is:
μ = E(x) = np
Then μ = 10*0.1 = 1
And the variance of x is:
V(x) = np(1-p)
V(x) = 10(0.1)(1-0.1)= 0.9
