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2 years ago

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A gardener has 27 pansies and 36 daisies.He plants an equal number of each type of flower in each row.What is the greatest possi

ble number of pansies in each row?

2 answers:

mojhsa [17]2 years ago

6 0

I think it might be 3 rows. Hope this helped

Dmitriy789 [7]2 years ago

3 0

Greatest number of pansies in each row is 9

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Look at the table below.

zlopas [31]

The Answer is A 1.2 :))))))))))))

4 0

2 years ago

Molly measured the diameter of her bike tire and found that it was 2 feet across. She estimated that for every turn of the tire,

natulia [17]

Answer:

Molly's estimation was approximately correct.

Step-by-step explanation:

Given:

Diameter of bike tire = 2 feet

Also Given:

She estimated that for every turn of the tire, the bike traveled about 6 feet.

Estimated Distance traveled = 6 feet

We need to find that whether her estimation reasonable.

Solution:

Now we know that Distance traveled is equal to Circumference of tire.

Since Tire is in circular shape.

We can say that;

Circumference of the tire will be π times diameter.

framing in equation form we get;

Circumference of the tire = $\pi \times 2 = 6.28 \ feet$

Now The actual distance traveled is 6.28 feet and Molly estimated as 6 feet.

Hence we can say that Molly's estimation was approximately correct.

5 0

2 years ago

Carlos drives 2 times the hours that patricia does. carlos and patricia drive for a total of 9 hours. how long did each person d

suter [353]

Patricia drove for 3 hours. Carlos drove for twice that, 6 hours. 6+3=9

4 0

2 years ago

I need help with this

rodikova [14]

You need to expand (4x-7)(x+3), multiplying each term in the first bracket by each term in the second bracket, in order to get 4x^2+5x-21. Hope that helps!

5 0

2 years ago

Read 2 more answers

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

2 years ago