Answer:
Q = Q
mcT = ml
100 x 4.2 x 25 = (50-18) l
l = 328
*Hope it helps*
Answer:
a) If the mass get double then the potential of the spring gets four times.
b) P'=3.848 J
Explanation:
Given that
P= 0.962 J
m = 3.5 kg
m'= 7 kg
Lets take extension in the spring is x when the mass 3.5 kg is attached to the spring.
m g = K x
K=Spring constant
We know that potential energy given as
If the mass get double then the potential of the spring gets four times.
P'= 4 P
When mass ,m' = 7 kg
Then potential will be
-----1
-------2
From equation 1 and 2
P'= 4 x 0.962 J
P'=3.848 J
Answer:
7174.09 N
Explanation:
Area = 7 ft x 4 x ft = 28 ft^2 = 2.60129 m^2
Pressure = 0.4 psi = 2757.9 Pa
Force = Pressure x Area
Force = 2757.9 x 2.60129 = 7174.09 N
25 meters per second.
To find this, divided 150 by 6 in order to get the correct calculation.
Hope this helps!