Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
Answer:
Step-by-step explanation:
(4+1)/(8-2)= 5/6
y + 1 = 5/6(x - 2)
y + 1 = 5/6x - 5/3
y + 3/3 = 5/6x - 5/3
y = 5/6x - 8/3
6(y = 5/6x - 8/3)
6y = 5x - 16
-5x + 6y = -16
General Idea:
W
hen we are given a point P(x, y) centered at origin with a scale factor of k, then the dilated point will be given by P' (kx, ky)
When, then P' is enlargement of P
When , then P' is reduction of P
Applying the concept:
In the diagram given A'B'C' is enlargement of ABC. So the correct option will be option A. , enlargement
Answer:
Step-by-step explanation:
Let
y ----> the length of the board
x ----> the width of the board
we know that
----> equation A
The area of the board is
----> equation B
substitute equation A in equation B