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2 years ago

Which electromagnetic waves have the shortest wavelength and the highest frequency? _________ waves

Physics

2 answers:

Ivan2 years ago

7 0

Answer:

Gamma waves

Explanation:

USPshnik [31]2 years ago

6 0

Answer:

Gamma

just took on eg

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How do line symmetry differ from rotational symmetry?.

sergeinik [125]

Answer:

A line of symmetry is a line that separates a shape into two identical halves.
Rotational symmetry is the same thing except when you rotate the object, it has to have the exact same line of symmetry.

<u><em>Hope this helps!!!</em></u>

3 0

2 years ago

Below is an oscilloscope trace from an AC supply. Calculate the frequency of the supply if each horizontal division represents 0

GuDViN [60]

Answer:

20 hertz of frequency produced.

Explanation:

$\boxed{frequency = \frac{1}{period} }$

Here we will find frequency and period should be in second, here given: 0.05 seconds

using the formula:

$\boxed{frequency = \frac{1}{0.05} }$

$\boxed{frequency =20}$

8 0

1 year ago

What is the resultant force on the human cannonball in the

Svetllana [295]

Answer:

heart

Explanation:

4 0

2 years ago

A mass of 1 kg is moving in a circle of radius 3.3 meters. What is the liner velocity v m/s that would give a Centripetal Force

Ghella [55]

Answer:

The linear velocity of the object is 8.71 m/s.

Explanation:

Given;

mass of the object, m = 1 kg

radius of the circle, r = 3.3 meters

centripetal force, F = 23 N

Centripetal force is given by;

$F_c = \frac{mv^2}{r}\\\\$

where;

v is the linear velocity of the object

$F_c = \frac{mv^2}{r}\\\\mv^2 = F_cr\\\\v^2 = \frac{F_cr}{m}\\\\v= \sqrt{\frac{F_cr}{m}} \\\\v= \sqrt{\frac{23*3.3}{1}}\\\\v = 8.71 \ m/s$

Therefore, the linear velocity of the object is 8.71 m/s.

4 0

2 years ago

Calculate the electric field strength required to just support an oil drop of mass

Ray Of Light [21]

Answer:

$E= 3.06 \times 10^{-17} N/C$

Explanation:

As we know that the oil drop experiment tells us the balancing the gravitational force by electrostatic force.

So ,

Electrostatic force = Gravitational force

qE=mg

Here , q is charge , E is electric field , m is mass and g is gravity.

so,

$E=\frac{mg}{q}$

Insert values from question,

$E=\frac{10^{-2}kg \times 9.8 m/s^{2}}{3.2 \times 10^{-19}C}$

$E= 3.06 \times 10^{-17} N/C$

This is the required value of electric field.

3 0

2 years ago