If a^2+b^2=c^2 then it's a right angle
If a^2+b^2>c^2 then it's acute
If a^2+b^2< c^2 then it's obtuse. 3.1^2+3^2. 5^2
1+9. < 25
#3 is obtuse
4. 28^2+45^2. 53^2
2809. 2809
#4 is a right triangle
5. 9^2+11^2. 13^2
81+ 121 =202.> 169
#5 is acute
an negative can't be a absolute value
<h2>
Answer:</h2>
The statement that best describes Imara's error is:
Option: D
D). She did not find the side lengths of the square with an area of 625.
<h2>
Step-by-step explanation:</h2>
Imara correctly did the previous calculation.
i.e. she correctly determined the area of square with side length 20 units (as 400 square units) and 15 units (i.e. 225 square units)
But when she sum the area of two squares then it won't give the length of hypotenuse it would give the area of a square.
Hence, the correct answer is:
Option: D
Answer:
{36, 38, 40, 42, 44}
Step-by-step explanation:
You are implying that you are adding up 5 consecutive numbers, and should use the word "add" or the word "sum."
"The sum of 5 consecutive odd numbers is 200" leads to:
x + (x+2) + (x+4) + (x+6) + (x+8) = 200. Note how each number is 2 more than the number preceding it. In this way you can guarantee that all of the 5 numbers are odd.
Summing up, we get 5x + 20 = 200, or 5x = 180.
Dividing both sides by 5, we get x = 36.
Then the 5 consecutive integers are
{36, 38, 40, 42, 44}. These add up to 200.
Unfortunately, these are consecutive EVEN numbers, not odd numbers.
Please ensure that you have copied down this problem correctly.
I would say D. It makes the most Since