Be E.N.D.bddndmmfmddndnxncnfnd
14/4 > 1 is what it looks like.
Answer:
see explanation
Step-by-step explanation:
Inequalities of the type | x | > a, always have solutions of the form
x < - a or x > a
This can be extended to expressions, that is
14 - 5x < - 8 OR 14 - 5x > 8 ( subtract 14 from both sides of both inequalities )
- 5x < - 22 OR - 5x > - 6
Divide both sides by - 5 , reversing the inequality sign as a consequence
x > OR x <
That is the solution is
x < OR x >
Answer:
Step-by-step explanation:
7x + 3 = 3x + 35
4x + 3 = 35
4x = 32
x = 8
Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}