Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18
<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
I agree with you because theta could be acute or obtuse, and if obtuse, negative value.
The answer is 2,2
as 3*2 - 2 = 4
ans 2*2 +2 = 4
So it satisfies both eqautions
Answer:
The answer would be 4,450
Step-by-step explanation:
:)