Question

Which of the following have both 2 and -5 as solutions.

Answer 1

$x_1=2\ \ \ and\ \ \ x_2=-5\\\\ \Rightarrow\ \ \ (x-x_1)(x-x_2)=(x-2)(x+5)=x^2+5x-2x-10=\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =x^2+3x-10\ \ \ \Rightarrow\ \ \ Ans.\ a.$

Answer 2

$x_1=2;\ x_2=-5\\\\(x-2)(x-(-5))=(x-2)(x+5)=x^2+5x-2x-10=x^2+3x-10\\\\Answer:a.$