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2 years ago

14

What’s the answer to this

1 answer:

Ipatiy [6.2K]2 years ago

7 0

2.4/0.3=8
0.3x8=2.4
The scale factor is 8.

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So I believe the problem is this:

$\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}$

where we are asked to find values for $a$ and $b$ such that the equation holds for any $x$ in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

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As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

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Divide both sides by 10:

$\frac{30}{10}=a$

$3=a$

So $a=3$ and $b=5$ .

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