Answer: 0.0624 atm
Explanation:-
According to the ideal gas equation:
P = Pressure of the gas = ?
V= Volume of the gas = 45.0 L
T= Temperature of the gas = -10.0°C = 263 K 
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas
Moles of gas=
The pressure of sulfur hexafluoride gas in the reaction vessel after the reaction is 0.0624 atm
Answer:
try looking the equations or find a calulator for those type of eqautions
Explanation:
Enthalpy change during the dissolution process = m c ΔT,
here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
= -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)
Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>
it described a nucleus surrounded by a large volume of space.
