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2 years ago

Suppose f(x)=2×+5 find the value of -2f(x+1)

1 answer:

3 0

F(x) = 2x + 5

-----------------------------------
Find f(x + 1) :
-----------------------------------
f(x +1) = 2(x + 1) + 5
f(x +1) = 2x + 2 + 5
f(x + 1) = 2x + 5

-----------------------------------
Find -2f(x+1):
-----------------------------------
-2(fx+1) = -2(2x + 5)
-2(fx+1) = -4x - 10

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Answer: -2(fx+1) = -4x - 10
----------------------------------------------------------------------

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Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

quadratic equation
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<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

<h3>tips and formulas:</h3>

<u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
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<h3>let's solve: </h3>

$step - 1 : \: define$

$- 4 {t}^{2} + 12t + 100 = 0$

$step - 2 : \\ divide \: both \: sides \: by \: - 4$

${t}^{2} - 3t - 25 = 0$

$step - 3 : \\ solve \: the \: quadratic$

$formula : \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

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$t = \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 } }{2.1}$

$t = \frac{ 3± \sqrt{ 9 + 100} }{2}$

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$t = \frac{3 - \sqrt{ 109 } }{2}$

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