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2 years ago

What does the rf value describe on a microscopic level why is this important?

Chemistry

1 answer:

lys-0071 [83]2 years ago

8 0

Answer: The retention factor describes the rate at which a compound migrates on a microscopic level.

The retention factor (Value) serves as a simple measurement of the relative binding of the compound of interest under the experimental conditions.

Retention factor values are used in identification purposes;

• Use to determine the affinity of the solute to the solvent

• Greater retention factor means greater affinity of solute to the solvent

Explanation:

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When 0.491 grams of a protein were dissolved in 44 mL of benzene at 24.4 degrees C, the osmotic pressure was found to be 50.9 to

Ira Lisetskai [31]

Answer:

4057.85 g/mol

Explanation:

Hello, the numerical procedure is shown in the attached file.

- In this case, since we don't have the density of the protein, we must assume that the volume of the solution is solely given by the benzene's volume, in order to obtain the moles of the solute (protein).

-Van't Hoff factor is assumed to be one.

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2 years ago

If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground what is the final veloci

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2 years ago

Name the two products when calcium carbonate (CaCO3) is heated

trapecia [35]

Answer:

The products are Calcium oxide and Carbon dioxide.

Explanation:

When calcium carbonate is heated, thermal decomposition occurs.

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2 years ago

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A main group metal was studied and found to exhibit the following properties:

Alecsey [184]

Answer: we learned this not to long ago i think its a,c

Explanation:

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2 years ago

If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol

igomit [66]

Answer:

$\Delta _RH=4x10^{-3}\frac{kJ}{mol}$

Explanation:

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In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

$\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}$

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

$\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}$

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2 years ago