Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
36 cm
Step-by-step explanation:
Let x represent the multiplier of the ratio units. Then the perimeter is the sum of the side lengths:
77 = 25 + 4x +9x
52 = 13x . . . . . . . . subtract 25
x = 4 . . . . . . . . . divide by 13
4x = 4(4) = 16 . . . . find the other side lengths
9x = 9(4) = 36
The side lengths are 25 cm, 16 cm, 36 cm. The longest side is 36 cm.
Answer:
4(5+6) = Distribute
20 + 24 = Add
44
Step-by-step explanation:
I don't really understand what you're asking, but if you're asking the sum of 8 plus 10, it's 18. Sorry if I didn't help, you can try clarifying though :)