Insert the point, (5,-2) with the slope of the line to figure out the equation. You can either use point-slope form, or plug it for for slope-intercept form.
Slope-intercept form:
-2 = -2(5) + b
-2 = -10 + b
Add 10 on both sides
8 = b
Thus,
y = -2x + 8
Answer is B
Answer:
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be : 4048.17
Step-by-step explanation:
3000 deposit amount, 2.9 compound monthly interest . save 80 dollars per month at home .
A=p(1+r)^t
A=3000(1+0.029/12)^12t
A=3000(1.002417)^12t dollars
for the amount saved at home=80*12t=960t dollars
C(t)=3000(1.002417)^12t+960t
if T=1 year then the saving will be :
C(t)=3000(1.002417)^12t+960t
=3088.17+960= 4048.17 dollars
Answer:
The correct answer is A. 15.2 units
Step-by-step explanation:
The segment AB is congruent to the segment BC eg AB≅BC Why?
We can prove it with the triangle congruent theorem, postulate side-side-angle
We are watching triangle ΔABO and triangle ΔCBO, they are congruent
first element side OB=OB - common side
second element side OA=OC=r - radius of the circle
third element angle ∡ABO≅∡CBO=90°
According to the postulate side-side-angle we can conclude that triangles
ΔABO≅ΔCBO (triangles are congruent)
If they are congruent all of their elements are also congruent and therefore also
side AB=BC => AB+BC=AC, which is chord => 7.6+7.6=15.2 units
AC= 15.2 units ( chord )
Good luck!!!
First you need to figure out the slope:
y2-y1/x2-x1=(1+5)/(-5-7)=-1/2
y+5=-1/2(x-7)
y=-1/2x-3/2
Step-by-step explanation:
The upstream speed is S / t₁, and the downstream speed is S / t₂.
If we say f is the speed of the fish in calm water, and r is the speed of the river, then:
f − r = S / t₁
f + r = S / t₂
If we say T is the time it takes to cross the river, then the speed perpendicular to the river is ℓ/T, the speed parallel to the river is r, and the overall speed is f.
Using Pythagorean theorem:
f² = (ℓ/T)² + r²
f² − r² = (ℓ/T)²
(f − r) (f + r) = (ℓ/T)²
(S / t₁) (S / t₂) = (ℓ/T)²
S² / (t₁ t₂) = (ℓ/T)²
(t₁ t₂) / S² = (T/ℓ)²
√(t₁ t₂) / S = T/ℓ
T = ℓ√(t₁ t₂) / S
