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2 years ago

A car traveled 112.0m in 24.500s, what was a car’s average speed?

Physics

1 answer:

kodGreya [7K]2 years ago

3 0

Average speed of the car is 4.57 m/s

Explanation:

Speed is calculated by the rate of change of displacement.

It is given by the formula, Speed = Distance/Time

Here, distance = 112 m and time = 24.5 s

Speed of the car = 112/24.5 = 4.57 m/s

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2 years ago

Peter does 3,000 joules (J) of work by moving an object 40 meters (m). What is the force that Peter applies to the object? A 75

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The force that peter applies to the object of distance 40m is 75N.

<h3>HOW TO CALCULATE FORCE</h3>

The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;

Force = Work done ÷ distance

According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:

Force = 3000J ÷ 40m

Force = 75N

Therefore, the force that peter applies to the object of distance 40m is 75N.

Learn more about force at: brainly.com/question/26115859

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1 year ago

A bungee jumper hangs from a bungee cord with zero velocity. If the bungee

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2 years ago

An airplane has an effective wing surface area of 17.0 m2 that is generating the lift force. In level flight the air speed over

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To solve this problem it is necessary to apply the equations given from Bernoulli's principle, which describes the behavior of a liquid moving along a streamline. Mathematically this expression can be given as,

$P_1 + \frac{1}{2}\rho*v_1^2 + P_2 + \frac{1}{2}*\rho*v_2^2=0$

Where,

$P_i =$ Pressure at each state

$\rho$ = Density

$v_i =$ Velocity

Re-organizing the expression we can get that

$P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2)$

Our values are given as

$v_1 = 40m/s$

$v_2 = 55m/s$

$\rho_{water} = 1.2kg/m^3 \rightarrow$ Normal Conditions

Replacing we have,

$P_1 -P_2 = \frac{1}{2}*1.2*(55^2-40^2)$

$P_1 - P_2 = 855Pa$

If we consider that there is a balance between the two states, the Force provided by gravity is equivalent to the Support Force, therefore

$F_l = F_g$

Here the lift force is the product between the pressure difference previously found by the effective area of the aircraft, while the Force of gravity represents the weight. There,

$F_g = W$

$F_l = (P_2-P_1)A$

Equating,

$(P_1 - P_2)*A = W$

$W = 855*17$

$W = 14535 N$

Therefore the weight of the plane is 14535N

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2 years ago