Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
Answer:
46 and 277
Step-by-step explanation:
Given
f(x) = - 8x - 11 ← substitute x = 3, x = - 4 into f(x)
f(3) = - 8(3) - 11 = 81 - 24 - 11 = 81 - 35 = 46
f(- 4) = - 8(- 4) - 11 = 256 + 32 - 11 = 288 - 11 = 277