X + 6 = 33
x = 27
hope this helps :D
Answer:
26 bags
Step-by-step explanation:
A bag of cat chows = 30 lbs
Amount of cat chows needed in a week = 15 lbs = ½ bag of cat chow
There are at least 52 weeks in a year.
The least number of cat chows bags needed at the shelter in 1 year = 52 weeks × ½ bag of chow
= 52 × ½
= 52/2
= 26 bags of cat chow
At least, 26 bags would be needed in 1 year (52 weeks) at this wild life shelter if 15 lbs is consumed weekly.
Answer:
Step-by-step explanation:
Given that X, the number of square feet per house is N(mean, 137)
Sample size = 19
Sample mean x bar =1350 sq ft
Since population std dev is given,
std error of sample =
Since sample size is small, t critical value can be used
df = 18
t value for 80% two tailed = 1.333
Margin of error = ±1.333(std error) = ±
Confidence interval = sample mean ±margin of error
=
Answer:
The answer is <u>8</u>.
Step-by-step explanation:
Given:
4d - 35= -3.
Now, the solution:
Adding both sides by 35 we get:
Dividing both sides by 4 we get:
Therefore, the answer is 8.