Answer:
1.Magnetosphere
2.Liquid Outer core
3.Atmosphere
4.Lightening
5.Biosphere
6.Blue
7.Dolphins
8.Hydrosphere
9.Ice Caps
10.Lithosphere
11.Latitude
12.Longitude
Explanation:
The invisible field that protect us from solar radiation is called Magnetosphere.
This protective field is created by movement between solid inner core and earth's Liquid outer core.
The layer of gases is called atmosphere.
In addition to wind , rain , lightening is observed on stormy night.
Because of water earth looks Blue.
Dolphins are just one of the animals that calls the hydrosphere, its home.
Ice caps in the north and south poles.
Rocky layer of solid earth is part of Lithosphere.
Look for the latitude first ,horizontal line ...
A complex, ML₆²⁺, is violet. The same metal forms a complex with another ligand, Q, that creates a weaker field. MQ₆²⁺, be expected to show green color.
<h3>What is spectrochemical series?</h3>
The ligands (attachment to a metal ion) are listed in the spectrochemical series according to the strength of their field. The series has been created by superimposing several sequences discovered through spectroscopic research because it is impossible to produce the full series by examining complexes with a single metal ion. The halides are referred to be weak-field ligands whereas the ligands cyanide and CO are strong-field ligands. Medium field effects are claimed to be produced by ligands like water and ammonia.
To know more about the spectrochemical series, visit:
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Answer:
<u> </u>H2 + <u>2</u><u> </u> Cl2 = <u>2</u><u> </u> HCl2
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl
Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.
To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH
Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH
Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH
Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH
I hope this helps.