Hey there, we are given quite a lot of information in this problem. First of all, let's make an equation.
y = x - 22
where y = student's age
where x = instructor's age
this equation is correct because x(instructor) - 22 will yield the student's age (y).
If the instructor were 44 years old, the student would be 22 years old.
y = 44 - 22
y = 22
If the instructor were 66 years old, the student would be 44 years old.
y = 66 - 22
y = 44
Answer:
θ=0,π/3,π,5π/3,2π
Step-by-step explanation:
cosθ sinθ-1/2 sinθ=0
sinθ(cos θ-1/2)=0
Either sin θ=0
θ=0,π,2π
or
cosθ-1/2=0
cos θ=1/2=cos π/3,cos(2π-π/3)
θ=π/3,5π/3
http://www.purplemath.com/modules/specfact.htm