2 years ago

Why the center of Newton rings is dark?

2 answers:

3 0

The point of contact the path difference is zero but one of the interfering ray is reflected so the effective path difference becomes λ/2 thus the condition of minimum intensity is created in the center.

grandymaker [24]2 years ago

3 0

Answer:

the point of contact Thè path different is zero but

<h3>one of inter ferying ray is reflected so the effective path difference become<u> </u><u>/</u> 2 and in this condition minimum intensity is created at center so the center of Newton ring is dark</h3>

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Electric Field of Ring of Charge A ring shaped charge has a radius of 0.250 meters and bears a total charge of +5.00 C What is t

Eduardwww [97]

Answer:

6.44 × 10^10 N/C

Explanation:

Electric field due to the ring on its axis is given by

E = K q r / (r^2 + x^2)^3/2

Where r be the radius of ring and x be the distance of point from the centre of ring and q be the charge on ring.

r = 0.25 m, x = 0.5 m, q = 5 C

K = 9 × 10^9 Nm^2/C^2

E = 9 × 10^9 × 5 × 0.25 / (0.0625 + 0.25)^3/2