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2 years ago

If x/y + y/x = -1 , find the value of x^3 - y^3

Mathematics

1 answer:

marin [14]2 years ago

7 0

Answer:

Step-by-step explanation:

Multiplying the first equation by xy, we have ...

x^2 +y^2 = -xy

Factoring the expression of interest, we have ...

x^3 -y^3 = (x -y)(x^2 +xy +y^2)

Substituting for xy using the first expression we found, this is ...

x^3 -y^3 = (x -y)(x^2 -(x^2 +y^2) +y^2) = (x -y)(0) = 0

The value of x^3 -y^3 is 0.

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lawyer [7]

Hello Love!! ♡　

»»————- $\red{Answer\:}$ ————-««

$\Huge{\boxed{\frac{1}{4}}}$

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$\mathfrak{apply~the~fraction~rule~:}~\frac{a}{c}~ -~\frac{b}{c} = \frac{a~-~b}{c}$

$= \frac{3-1}{8}$

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$=\frac{2}{8}$

$\mathfrak{cancel~the~numbers~:}~\frac{2}{8} = \frac{1}{4}$

$=\frac{1}{4}$

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2 years ago

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IceJOKER [234]

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2 years ago

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8x10^6 is how many time as great as 4x10^3

Nataly_w [17]

Answer:

2x10^3

Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

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2 years ago

Let f(x) = 2x - 1, g(x) = x²- 2 x+ 1. find (f• g ) (x)

Nana76 [90]

Answer:

f•g(x) = f(x)•g(x)

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2 years ago

Can somebody help me with this?

icang [17]

We are given polynomial: $5x^3+8x^2-7x-6$ .

We need to explain why the binomial (x + 2) IS a factor of this polynomial expression and why the binomial (x + 1) IS NOT a factor of this polynomial expression.

Let us set first factor equal to 0 and solve for x.

x+2=0

x=-2.

Plugging x=-2 in given polynomial, we get

$5(-2)^3+8(-2)^2-7(-2)-6 = 5(-8) +8(4)+14-6$

$= -40 +32+14-6$

$=0$

Because x=-2 gives 0 on plugging in given polynomial, so it's factor of given polynomial expression.

Now, let us check second factor x+1=0

x=-1.

Plugging x=-1 in given polynomial, we get

$5(-1)^3+8(-1)^2-7(-1)-6 = 5(-1) +8(1)+7-6$

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= -4.

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2 years ago