Answer:
5a. 4w+24≤100
5b. Dimensions=31ft x 19 ft
Area = 589ft²
Step-by-step explanation:
l=w+12
p=2l+2w
p=2(w+12)+2w
p=2w+24+2w
p=4w+24
The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:
4w+24≤100
For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)
100=4w+24
4w=76
w=19ft
l=19+12
l=31ft
The dimensions are 31ft x 19ft.
Area=lw
=31*19
=589ft²
<u>1</u><u> </u> x-y = 10
2
multiply by 2
2* (<u>1</u> x+y) =10
x+y=20
16
x + 1 = -x + (-5)
2x + 1 = -5
2x = -6
x = -3
