Answer:
2.5 s, 5 m
Explanation:
The equations for the horizontal and vertical position of Lukalu are:
we can find the time it takes her to reach the ground by requiring that the vertical position becomes zero:
y(t) = 0
So we find:
The horizontal distance of Lukalu instead will be given by the equation for the horizontal position, substituting t = 2.5 s:
Answer:
Explanation:
Given
Initial speed
distance traveled before coming to rest
using equation of motion
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
for
using same relation we get
divide 1 and 2 we get
So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed
Answer:
they say yum yum as they eat planets and make humans starve
Explanation:
but they still eat them
Answer:
0.114 kg or 114 g
Explanation:
From the diagram attaches,
Taking the moment about the fulcrum,
sum of clockwise moment = sum of anticlockwise moment.
Wd = W'd'
Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.
make W' the subject of the equation
W' = Wd/d'................ Equation 1
Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm
Substitute these values into equation 1
W' = 0.5047(23.2)/10.5
W' = 1.115 N.
But,
m' = W'/g
m' = 1.115/9.8
m' = 0.114 kg
m' = 114 g
Answer:
15.45 m/s
Explanation:
F = 1.2 x 10^3 N, Fk = 615 N, u = 0, s = 25 m
Let the speed after traveling 25 m is v.
mass = F / g = 1200 / 9.8 = 122.45 kg
Net force, Fnet = 1.2 x 1000 - 615 = 1200 - 615 = 585 N
acceleration = Fnet / mass = 585 / 122.45 = 4.78 m/s^2
Use third equation of motion
v^2 = u^2 + 2 a s
v^2 = 0 + 2 x 4.78 x 25 = 238.88
v = 15.45 m/s