Write an equation for the hyperbola with vertices (-7,0) and (7,0), conjugate axis of length of 10?
1 answer:
The hyperbola is more or less as in the picture below
notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component
the conjugate axis is 10, notice the length of the "b" component
thus
so, hmmmm plug in those values
notice the traverse axis is horizontal, meaning the positive fraction will be the one with the "x" variable in it, and notice the length of the "a" component
the conjugate axis is 10, notice the length of the "b" component
thus
so, hmmmm plug in those values
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Total area = 104+24 = 128 sq.in , Option C is the right answer.
The missing figure is attached with the answer.
<h3>What is Area ?</h3>The space occupied by a two dimensional figure is called Area.
The figure given in the question can be divided into two figure
A rectangle of 8 * 13 inch
and a triangle of 8 * 6 inch
The area of a rectangle is given by
Length * Breadth
8 * 13
= 104 sq.inch
The area of the triangle is given by
(1/2) * base * height
= (1/2) * 8 * 6
= 24 sq.inch
Total area = 104+24 = 128 sq.in
Therefore Option C is the right answer.
To know more about Area
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