Answer: 40
Step-by-step explanation:
4n+8=2(n+6)
Now isolate the n on one side of the equation:
4n+8=2n+12(distribution of the 2)
4n=2n+4(combine like terms)
2n=4(combine like variables)
N=2(isolate the n)
The answer is 2
Good luck!
Answer:
4 t - 7 = 2 t+ 13 is the required equation.
The number of race medals Tara has is t = 20 medals.
Step-by-step explanation:
Let the number of medals Tara has = t medals
So, the number of medal Anita has = 4( Medals of Tara) - 7
= 4t - 7
And the number of medals Gary has = 2 times (Medals of Tara) + 13
= 2(t) + 13 = 2t + 13
Now, Annita and Gary has same number of medals.
⇒ 4t - 7 = 2t+ 13
or, 4t - 2t = 7 + 13
⇒ 2t = 20
⇒ t = 20/2 = 10
or t = 10
Hence, the number of race medals Tara has is t = 20 medals
Answer:
C. 5^8
to raise a power to another power, multiply the exponents
then multiply thr numbers
then u get 5^8
Answer:
The GCF for the variable part is
k
Step-by-step explanation:
Since
18
k
,
15
k
3
contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.
Steps to find the GCF for
18
k
,
15
k
3
:
1. Find the GCF for the numerical part
18
,
15
2. Find the GCF for the variable part
k
1
,
k
3
3. Multiply the values together
Find the common factors for the numerical part:
18
,
15
The factors for
18
are
1
,
2
,
3
,
6
,
9
,
18
.
Tap for more steps...
1
,
2
,
3
,
6
,
9
,
18
The factors for
15
are
1
,
3
,
5
,
15
.
Tap for more steps...
1
,
3
,
5
,
15
List all the factors for
18
,
15
to find the common factors.
18
:
1
,
2
,
3
,
6
,
9
,
18
15
:
1
,
3
,
5
,
15
The common factors for
18
,
15
are
1
,
3
.
1
,
3
The GCF for the numerical part is
3
.
GCF
Numerical
=
3
Next, find the common factors for the variable part:
k
,
k
3
The factor for
k
1
is
k
itself.
k
The factors for
k
3
are
k
⋅
k
⋅
k
.
k
⋅
k
⋅
k
List all the factors for
k
1
,
k
3
to find the common factors.
k
1
=
k
k
3
=
k
⋅
k
⋅
k
The common factor for the variables
k
1
,
k
3
is
k
.
k
The GCF for the variable part is
k
.
GCF
Variable
=
k
Multiply the GCF of the numerical part
3
and the GCF of the variable part
k
.
3
k