Answer:
This is very detailed as I wish to make some principles about fractions clear.
3
5
12
Explanation:
This question boils down to
3
2
3
−
1
4
A fractions structure is that of:
count
size indicator of what you are counting
→
numerator
denominator
You can not directly add or subtract the counts (numerators) unless the size indicators (denominators) are the same.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
3
2
3
Write as
3
+
2
3
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its true value
[
3
×
1
]
+
2
3
[
3
×
3
3
]
+
2
3
9
3
+
2
3
=
11
3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Putting it all together
3
2
3
−
1
4
→
11
3
−
1
4
But the size indicators are not the same. I chose to make them become 12
11
3
−
1
4
→
[
11
3
×
1
]
−
[
1
4
×
1
]
→
[
11
3
×
4
4
]
−
[
1
4
×
3
3
]
→
44
12
−
3
12
Now we may subtract the counts
→
44
−
3
12
=
41
12
But this is the same as
12
12
+
12
12
+
12
12
+
5
12
=
1
2
+
2
1
2
+
2
1
2
+
5
12
=
3
5
12
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Answer:
horizontal
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that there is a function of x,
Let us find first and second derivative for f(x)
When f'(x) =0 we have tanx = 1 and hence
a) f'(x) >0 for I and III quadrant
Hence increasing in 
and decreasing in 
Hence f has a maxima at x = pi/4 and minima at x = 3pi/4
b) Maximum value = 
Minimum value = 
c)
f"(x) =0 gives tanx =-1
are points of inflection.
concave up in (3pi/4,7pi/4)
and concave down in (0,3pi/4)U(7pi/4,2pi)
Answer:
x = 6 and y = - 6
Step-by-step explanation:
- 4 x - 2 y = -12.......equ No 1
4 x + 8y = - 24.......equ No 2
Adding equ No 1 and equ No 2
6 y = - 36
∴ y = - 6
substitute y = - 6 in equ No 2
4 x + 8 y = -24
4 x + 8 ×( -6) = - 24
4 x - 48 = -24
4 x = -24 + 48
4 x = 24
∴ x = 6
x = 6 and y = - 6
