Okay, so my last answer was deleted because I didnt show any work.
According to the rule,
a+b>c
c+b>a
c+a>b
so...
2+3=6...6<7
21+23=44...44+44
12+36=48...48<53
14+17=31...31>30
Since answer D is the only answer that fullfills the rule a+b>c, it is the correct answer
Seven thousand two hundred thirty one divided by twenty-four
5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 <span>The smallest integer in our sequence is 2n = 2*17 = 34</span> Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70
Answer:
3m+3p
Step-by-step explanation:
Sum of m and p is expressed as;
m + p (sum means addition)
If 3 is multiplied by the sum, this is expressed as;
3(m+p)
Expand
3m + 3p
Hence the required expression is 3m+3p
Answer:
Child tickets are 97
Step-by-step explanation:
x + y = 175 ...............(1)
x = 175 - y
5.90x + 9.10y = 1282.10. .........(2)
5.90 (175 - y) + 9.10y = 1282.10
1032.50 - 5.9y + 9.10y = 1282.10
3.2y = 249.60
y = 249.6. / 3.2
y = 78
From equation 1
x + y = 175
x + 78 = 175
x = 175 - 78
x = 97
