Answer:
According to Hardy Weinberg law (p+q)2=1 where p is fequency of one allele and q is the frequency of another allele.
According the question
q represent the short legs and 33 of 100 organism have short legs.
As a result the frequency of q with respect to the 100 organism is 33/100
=0.33
Therefore q=0.33
we all know that
(p+q)2=1
∴ p+q= 1
∴ p=1-q
p= 1-0.33
p=0.67
The frequency of p is 0.67
Explanation:
Relating to development involves the specialization of CELLS by form and function, and NOT the entire organism?
differentiation, morphogenesis or growth?
I think the answer is differentiation.
Answer:
The correct option is C - Professor Scrawll applied 100 nM BurD to the cells for 24 hours, while Dr. Bogey applied 1 nM BurD to the cells for 12 hours.
Explanation:
The correct option is C - Professor Scrawll applied 100 nM BurD to the cells for 24 hours, while Dr. Bogey applied 1 nM BurD to the cells for 12 hours.
As the exotoxin, BurD is very stable and lyse the ankle cells very quickly, more concentration and more time of action should only lyse the cells. Perhaps Dr.Bogey's ankle cells were not lysed because the concentration she used was only 1nM compared to the 100nM concentration used by Dr. Scrawll, and the time period of incubation was only 12 hours compared to the 24 hours used by Dr. Scrawll.
Considering the other explanations given in the remaining options, the concentration and time of incubation used by Dr. Bogey are more than that used by Dr. Scrawll which should only have possibly lysed the cells. Moreover, contamination with bleach also should have only lysed the cells.
Because at that point, the egg would already be fertilized. Now in cases like identical twins, two sperm must enter the egg at the exact same time.
