Answer:
740
Step-by-step explanation:
The n th term of an arithmetic series is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then
a₁ + 2d = 7 → (1)
a₁ + 6d = 23 → (2)
Subtract (1) from (2) term by term
4d = 16 ( divide both sides by 4 )
d = 4
Substitute d = 4 into (1)
a₁ + 2(4) = 7
a₁ + 8 = 7 ( subtract 8 from both sides )
a₁ = - 1
The sum to n terms of an arithmetic series is
= [ 2a₁ + (n - 1)d ] , thus
= [ (2 × - 1) + (19 × 4) ]
= 10(- 2 + 76) = 10 × 74 = 740
Si estas haciendo una linea recta vas a necesitar dos puntos. Los encuentras poniendo un numero por x en la formula para que te de un numero, y. Y te va dar (x, y). Lo haces otravez con otro valor de x y ese te va dar (x2, y2). Y luego los conectas con una linea.
Answer:
7
Step-by-step explanation:
Use secant-tangent product theorem.
1. Set up the equation
(x-3)(x-3+5) = (x-1)²
2. Solve
(x-3)(x+2) = (x²-2x+1)
(x²-x-6) = (x²-2x+1)
3. Solve for x
Subtract x² from both sides
-x-6 = -2x+1
Add 2x and 6 to both sides
x = 7
The first thing you should observe in the graph is that
6x + 4y = 24 is a line with a negative slope.
2x-4y = -8 is a line with positive slope.
After you identify the functions you can choose the correct affirmations.
The x-coordinate of the solution is 2. The y-coordinate of the solution is 3. The ordered pair that is the solution to the system lies in Quadrant I.