" Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).1. = [3x + 2] + [4 – 5x] = 3x + 2 + 4 – 5x. = 3x – 5x + 2 + 4. = –2x + 6. (f – g)(x) 2. = f (x) – g(x)= [3x + 2] – [4 – 5x] = 3x + 2 – 4 + 5x. = 3x + 5x + 2 – 4. = 8x– 2. 3. ...= (3x + 2)(4 – 5x) = 12x + 8 – 15x2 – 10x. = –15x2 + 2x + 8. " - Google
The answer will be 61,440
Answer:
(a) 1, 2, 3, 6, 8
Step-by-step explanation:
Given
Required
The sequence of hours worked each day
<em>See attachment for options</em>
From the question, we understand that:
This means that, the middle number is 3 (when sorted)
So, we can conclude that (b) and (c) cannot be true because their middle numbers are 6 and 5 respectively
Next, is to determine the mean of (a) and (d)
The mean of a data is calculated as:
So, we have:
(a)
(d)
Option (a) is true, because it has:
Answer:
x=50/3y
y=50/3x
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.