Parallel lines, have the same slope, so the slope of the line through 0,0 and -2,-12, is the same as for the line running through (6/5,-19.5) as well, so what is it anyway?
so, we're looking for the equation of a line whose slope is 6, and goes through (6/5,-19/5)
Answer:
Degree = 4
Step-by-step explanation:
For the given conditions:
n = 4
i and 5i are zeros
f(-2) = 145
For zeros, it means they are a quadratic factor of the expression
It means, we will have x = ± i and x = ± 5i
therefore, the given factors are (x - i)(x + i)(x - 5i)(x + 5i)
Hence, we have the function
given degree = 4
f(x) = a(x-i)(x+i)(x-5i)(x+5i)
f(x) = a(x² + 1)(x² + 25)
Hence, substituting -2 for x, we have
f(-2) = a(5)(29) = 145
Hence, a = 1
f(x) = x⁴ + 26x² + 25
Therefore, we can see that the given degree = 4
We can solve this by using the P<span>ythagorean theorem which is below:
Or we can say
</span>
<span>w = widht
h = height
d = diagonal measure
With that said, we know the height is .75 times the width so .75w. We also know d = 34, which is our diagonal measure.
w = don't know yet but need to find
h = .75w
d = 34
Now lets plugin the information we know into our equation</span>
Now lets to the mathCombine like termsDivide both sides of the equal sign by 1.5625Now take the square root on both sides of the equal signSo the width is 27.2
We can check this by putting 27.2 back into our original equation
Answer: Multiply the divisor and dividend by 10
Answer:
23 and 131
Step-by-step explanation:
For the first one. Since a whole entire angle thingie is 360, subtract 243 and 94 from 360. Answer is 23 :)
For the second one. This is a supplementary angle. 180- 49 is 131. Your done!