No, they are both incorrect by my understanding of your question use the Pythagorean theorem a^2 + b^2 =c^, therefore, 7^2 +x^2 = 13^2 or 49+x=169 then solve normally 169-49=120 √120 =5
The answer is 5
Answer:
1.
x=-10
x=-6
2.
x=10
x=-3
Step-by-step explanation:
to find the zeros of a function you need to set it equal to zero:
x^2+16x+60=0
then you factor
(x+10)(x+6)=0
then you have to finish factoring/simplifying
x+10=0
-10
x=-10
x+6=0
-6
x=-6
and the same thing for number 2
x^2-7x-30=0
(x-10)(x-3)=0
x=10, x=3
Assuming your question can be rewritten as:
"What number is 10% greater than 7,962"
7962 * 110% = itself + 10%
= 7962 * 1.10 <----- (1.10 = 110%)
= 8758.2
29.87 should be it hopefully
45-21 over 5-2 which would be 4 because it shows it
