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2 years ago

Seven and fifty-one thousands

2 answers:

5 0

Hello there.

Question: Seven and fifty-one thousands

Answer: It can be written as a mixed number:
7 $\frac{51}{1000}$

Hope This Helps You!
Good Luck Studying ^-^

vaieri [72.5K]2 years ago

4 0

7.0051 as a decimal.

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Which choices are equivalent to the fraction below? check all that apply 16/36

kenny6666 [7]

Answer:

$\frac{16}{36} = \frac{8}{18} = \frac{4}{9}$

Step-by-step explanation:

$\frac{16}{36} = \frac{16/4.5}{36/4.5} = \frac{3.5555}{8} \neq \frac{3}{8} \\\\\frac{16}{36} = \frac{16/12}{36/12} = \frac{1.3333}{3} \neq \frac{1}{3} \\\\\frac{16}{36} = \frac{16/9}{36/9} = \frac{1.7777}{4} \neq \frac{1}{4} \\\\\frac{16}{36} = \frac{16/4}{36/4} = \frac{4}{9} \\\\\frac{16}{36} = \frac{16/7.2}{36/7.2} = \frac{2,2222}{5} \neq \frac{2}{5} \\\\\frac{16}{36} = \frac{16/2}{36/2} = \frac{8}{18} \\\\$

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2 years ago

What is 2.85 tons rounded to the nearest hundreth?

ipn [44]

It already is rounded to the nearest hundredth

5 0

2 years ago

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What is the quotation -3/8 divided by -1/4

Bumek [7]

Answer:

3/2

Step-by-step explanation:

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2 years ago

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If x and y vary directly and x=25 when y=100 find x when y=24. PLEASE HELP FASTTTTTTT

Veseljchak [2.6K]

Answer:

x = 6

Step-by-step explanation:

Given that x and y vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition x = 25 when y = 100 , then

100 = 25k ( divide both sides by 25 )

4 = k

y = 4x ← equation of variation

When y = 24 , then

24 = 4x ( divide both sides by 4 )

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2 years ago

Drag a reason to each box to complete this proof. If 12=13x+5 , then x = 21.

Ainat [17]

I think the answers are:

Statement Reason
12=13x+5 Given
7=13x Subtraction Property of Equality
21 = x Multiplication Property of Equality
x = 21 Symmetric Property of Equality

By the way, I'm doing the same exam for Geometry as well. There's a lot of proof questions on there which I'm not good at doing for the reasoning part. If you finish the exam before I do, maybe you can message me what the answers are for some of the questions on there so I know if my answers for the questions are incorrect or not.

Besides that, hope the answer above is correct for you.

~ ShadowXReaper069

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2 years ago

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