AB = CD = √8 ≈ 2.8 units
BC = AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = 3.92 units²
Perimeter of the rectangle ABCD = 8.4 units
<h3>How to Find the Area and Perimeter of a Rectangle?</h3>
Given the coordinates of vertices of rectangle ABCD as:
- A(0,2)
- B(2,4)
- C(3,3)
- D(1,1)
To find the area and perimeter, use the distance formula to find the distance between A and B, and B and C.
Using the distance formula, we have the following:
AB = √[(2−0)² + (4−2)²]
AB = √[(2)² + (2)²]
AB = √8 ≈ 2.8 units
CD = √8 ≈ 2.8 units
BC = √[(2−3)² + (4−3)²]
BC = √[(−1)² + (1)²]
BC = √2 ≈ 1.4 units
AD = √2 ≈ 1.4 units
Area of the rectangle ABCD = (AB)(BC) = (2.8)(1.4) = 3.92 units²
Perimeter of the rectangle ABCD = 2(AB + BC) = 2(2.8 + 1.4) = 8.4 units
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25/4= 6.25
In one day, there are 6.25 letters.
Hope this helps!
Using equations we know that the value of x needs to be (E) 4 to make HL congruent to AC.
<h3>
What are equations?</h3>
A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
The point-slope form, standard form, and slope-intercept form are the three main types of linear equations.
So, HL is a hypotenuse that will be congruent to the hypotenuse AC.
We know that HL is 3x + 3.
Ac is 15.
Then the equation will be:
3x + 3 = 15
Now, solve the equation to get x as follows:
3x + 3 = 15
3x = 15 - 3
3x = 12
x = 12/3
x = 4
Therefore, the value of x needs to be (E) 4 to make HL congruent to AC.
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Correct question:
For the triangles to be congruent by hl, what must be the value of x?
a. 8
b. 9
c. 17
d. 3
e. 4
In order to make b the subject of this equation, we must isolate it on the left side. We can do this by following these steps:
Subtract b from both sides
Subtract P from both sides
Now, we have isolated b, but it is negative. We can fix this by multiplying both sides of the equation by -1.
Which is your final answer.
.
Hope that helped! =)