7th grade: 62/120 of the class is made up of girls; (120-62)/120 of boys.
8th grade: 58/120 of the class is made up of boys; (120-58)/120 of girls.

Looking at the info for boys only: Compare (120-62)/120 with 58/120. What do you see?

3 0

2 years ago

8x - 54 = 82 simplify

kirill [66]

Answer:

use brainly points

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the rectangular coordinates of the point with the polar coordinates ordered pair 7 comma 2 pi divided by 3.

Morgarella [4.7K]

Answer:

$\left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right)$ .

Step-by-step explanation:

The given point is

$\left(7,\dfrac{2\pi}{3}\right)$

We need to find the rectangular coordinates of the given point.

If a polar coordinate is $(r,\theta)$ , then

$x=r\cos theta$

$y=r\sin theta$

In the given point $\left(7,\dfrac{2\pi}{3}\right)$ ,

$r=7,\theta=\dfrac{2\pi}{3}$

Now,

$x=7\cos \dfrac{2\pi}{3}$

$x=7\cos \left(\pi-\dfrac{\pi}{3}\right)$

$x=-7\cos \left(\dfrac{\pi}{3}\right)$

$x=-7\left(\dfrac{1}{2}\right)$

$x=-\dfrac{7}{2}$

and,

$y=7\sin \dfrac{2\pi}{3}$

$y=7\sin \left(\pi-\dfrac{\pi}{3}\right)$

$y=7\sin \left(\dfrac{\pi}{3}\right)$

$y=7\left(\dfrac{\sqrt{3}}{2}\right)$

$y=\dfrac{7\sqrt{3}}{2}$

Therefore, the required point is $\left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right)$ .

3 0

2 years ago