Which quadratic function has one real solution? 0 = 2(x + 7)(x – 5) 0 = (x – 3)(x – 3) 0 = 2.4(x – 2)(x + 2) 0 = (x – 2)(x – 1)
2 answers:
0 = (x – 3)(x – 3)
x - 3 = 0
x = 3
Solution is x = 3 (one real solution)
Answer
0 = (x – 3)(x – 3)
Answer:
B
Step-by-step explanation:
0=2/3(x-3)(x-3)
did it on edge
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