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2 years ago

For each sequence, find the common difference.

Mathematics

1 answer:

Juliette [100K]2 years ago

8 0

Answer:

first is 18

second is 36

third is -10

fourth is -10

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EXPERTS/ACE/GENIUSES

Naddik [55]

1SF = 1 1/2 = 1.5
centered at origin

answer is
figures MNO and PNQ

6 0

2 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

2 years ago

(1 point) An insurance company offers its policyholders a number of different premium payment options. For a randomly selected p

Olegator [25]

Answer:

X | 1 3 5 7

f(X) | 0.4 0.2 0.2 0.2

b) $P(4$

Step-by-step explanation:

For this case we have defined the cumulative distribution function like this:

$F(X) = 0, x$

$F(X) = 0.4, 1 \leq x$

$F(X) = 0.6, 3 \leq x$

$F(X) = 0.8, 5 \leq x$

$F(X) = 1, x \geq 7$

And we know that the general definition for the distribution function is given by:

$F(x) = P(X \leq x) = \sum_{i\leq k} f(i)$

Where f represent the density function.

Part a

For this case we need to find the density function, so we can find the values for the density for each value of X = 1,2,3,4,5,6,7,... since X is a discrete random variable.

$f(1) = P(X=1) = P(X \leq 1) - P(X=0) = F(1) -F(0) = 0.4-0=0.4$