Answer:
The y-intercept represents the flat fee.
Step-by-step explanation:
The y-intercept on the graph would be the point at which the line cuts across or intercepts the y-axis. At this point, the value of x (miles travelled) would be 0. The y-intercept in this case, would be the flat fee which is given as $2.
At x = 0, f(0) = 2.
The y-intercept represents the flat fee on the graph of f(x).
Answer:
sorry is its complicated
Step-by-step explanation:
Find the components of the definition.
f
(
x
+
h
)
=
x
2
+
2
h
x
+
h
2
−
9
f
(
x
)
=
x
2
−
9
Plug in the components.
f
(
x
+
h
)
−
f
(
x
)
h
=
x
2
+
2
h
x
+
h
2
−
9
−
(
x
2
−
9
)
h
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
