Answer:
208
Step-by-step explanation:
{ed}-{3cb}+{4ba}-{2ea} = {(-15)*(-6)} - {3*5*(-2)} + {4*(-2)*4} - {2*(-15)*4}
={90} - {15*(-2)} + {16*(-2)} - {8*(-15)}
= {90} - {-30} + {-32} - {-120}
= 90 (--)30 (+-) 32 (--) 120
= 90 + 30 - 32 + 120
= 120 - 32 + 120
= 88 + 120
= 208
Answer:
156
Step-by-step explanation:
f(x)= 4^(2x) -100
Let x =2
f(2)= 4^(2*2) -100
= 4^4 - 100
= 256 -100
= 156
Answer:
<u>The number of pens = 120 and the number of pencils = 200</u>
Step-by-step explanation:
Let the number of pens x, and the number of pencils is y
the cost of one pen $1, and the cost of one pencil $0.5
The cost of the whole purchase was $220
1 * x + 0.5 * y = 220
x + 0.5 y = 220 ⇒ eq.(1)
there were 80 more pencils than pens
y - x = 80 ⇒ eq.(2)
from eq.(2) x = y - 80
By substitution with x from the last equation at eq.(1)
∴ (y - 80) + 0.5 y = 220
1.5y = 220 + 80 = 300
y = 300/1.5 = 200
x = y - 80 = 200 - 80 = 120
<u>So, the number of pens = 120 and the number of pencils = 200</u>
Answer:
hi
Step-by-step explanation:
first of all,we should do this:
1 year is 12 month
amd 4 year is 48 month(12×4)
then we must add 2 months (wich is given) to 48
He was 50 months old when he started school
and we should find how old is he now
11 ×12=132months
132+1=133months
133-50=83 ( he has been 83 months in school)
let's turn it to years 6 years 11 months
( for finding years you should divide 83 to 12)
hope it helps
Answer:
C
Step-by-step explanation:
It is C. Have a great day!
